H=-4.9t^2+1.5t

Solution for H=-4.9t^2+1.5t equation:

=-4.9H^2+1.5H

We move all terms to the left:

-(-4.9H^2+1.5H)=0

We get rid of parentheses

4.9H^2-1.5H=0

a = 4.9; b = -1.5; c = 0;
Δ = b2-4ac
Δ = -1.52-4·4.9·0
Δ = 2.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.5)-\sqrt{2.25}}{2*4.9}=\frac{1.5-\sqrt{2.25}}{9.8}
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.5)+\sqrt{2.25}}{2*4.9}=\frac{1.5+\sqrt{2.25}}{9.8}
$